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ipToInt32.rb
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31 lines (20 loc) · 811 Bytes
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=begin
Source: Codewars
Difficulty: 6 kyu
Title: IPv4 to int32
Description:
Take the following IPv4 address: 128.32.10.1
This address has 4 octets where each octet is a single byte (or 8 bits).
1st octet 128 has the binary representation: 10000000
2nd octet 32 has the binary representation: 00100000
3rd octet 10 has the binary representation: 00001010
4th octet 1 has the binary representation: 00000001
So 128.32.10.1 == 10000000.00100000.00001010.00000001
Because the above IP address has 32 bits, we can represent it as the 32 bit number: 2149583361.
Write a function ip_to_int32(ip) that takes an IPv4 address and returns a 32 bit number.
Example:
ip_to_int32("128.32.10.1") => 2149583361
=end
def ip_to_int32(ip)
("%08b%08b%08b%08b" % ip.split('.')).to_i(2)
end